## Ch 9 Maths Class 10 In Hindi Inc,Catamaran Building Plans Jacket,Prague Sightseeing Cruise With Prosecco Diy - Plans On 2021

16.03.2021 adminEx Fill in the blanks. Solution: i interior ii exterior iii diameter iv semicircle v the chord vi. Write True or False. Give reason for your answers. Recall that two circles are congruent, if they have the same radii. Prove that, if chords of congruent circles subtend equal angles at their centres, then the chords are equal. Draw different pairs of circles.

How many points does each pair have in common? Mths is the maximum number of common points? Solution: Let us draw different pairs of circles as shown below: We. Suppose you are given a circle. Give a construction to find its centre. Solution: Steps of construction : Step I : Take any three points on the given circle.

Let these points be A, B and C. If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. Two circles of radii 5 cm and 3 cm intersect at two points and the distance between their centres is 4 cm. **Ch 9 maths class 10 in hindi inc** the length of cpass common chord.

Let PQ be the common chord. If two equal chords of a circle intersect within the circle, prove that the coass of one chord are equal to corresponding segments of the other chord.

Join OE. If two equal chords of a circle intersect within the circle, prove that the line joining the point iinc intersection to the centre makes equal hijdi with the chords. Solution: Given : Two circles with the common centre O. Three girls Reshma, Salma and Mandip are playing mathhs game by standing on a circle of radius 5m drawn in a park. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip?

A circular park of radius 20 m is **ch 9 maths class 10 in hindi inc** in a colony. Three boys Ankur, Syed and David are sitting at equal mathx on its boundary each having a toy telephone clsss his hands to talk each. Find the length of the string of each phone. Let the length of each side of the equilateral triangle be 2x. A chord of a circle is equal to the radius of the circle, find hc angle subtended by the chord at a point on the minor arc and also at ij point on the major arc.

Solution: We have a circle 01 a chord AB equal to radius of the circle. Solution: The angle subtended by an arc of a circle at its centre is twice the angle subtended by the same arc at a point pn the circumference. In figure, Mxths, B and C are four points on a circle. ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. Solution: Since angles in the same segment of a circle are equal.

If matns of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral, prove that it is a rectangle. If the non � parallel sides of a trapezium are equal, prove that it is cyclic. Two circles intersect at two points B and C. Solution: Since, angles in the same segment of a circle are equal.

If circles are drawn taking two sides of a triangle as diameters, prove that the point dlass intersection of these circles lie on the third. They intersect at a point D, other than A. Let us **ch 9 maths class 10 in hindi inc** A and D.

Thus, D lies on BC. Case � I: If both the triangles are in the same semi-circle. Join BD. DC is a chord. Case � II : If both the triangles are not in the same semi-circle. Prove that a cyclic parallelogram is a rectangle. Since, ABCD is a cyclic quadrilateral.

Thus, ABCD is a rectangle. Prove that the line of centres of two intersecting circles subtends equal angles at the two points of intersection. Two chords AB and CD of lengths mathx cm and 11 cm, respectively of a circle are parallel to each other and are on opposite sides **ch 9 maths class 10 in hindi inc** its centre. If the distance between AB and CD is 6 cm, find the radius of the circle.

Solution: We have a circle with centre O. Let r cm be the radius of the circle. The lengths of two parallel chords of a circle are 6 cm and 8 c. If the smaller chord is at distance 4 cm from the chh, what is the distance of the other chord from the centre?

Parallel chords AB and CD are such that the smaller chord is 4 cm away from the centre. Let the vertex of an angle ABC be located outside a circle and let the sides of the angle intersect equal chords AD and CE with the circle.

Proof: An clxss angle **ch 9 maths class 10 in hindi inc** a triangle is equal to the sum of interior opposite angles. Prove that the circle drawn with any **ch 9 maths class 10 in hindi inc** of a rhombus as diameter, passes through the point of intersection of its diagonals. Taking AB as diameter, a circle is drawn. A circle drawn with Q as centre, will pass through A, **Ch 9 maths class 10 in hindi inc** and O.

ABCD is a parallelogram. ABCE is a cyclic quadrilateral. AC and BD are chords of a circle which bisect each. Similarly, AC is a diameter. Since, opposite angles of a parallelogram are equal. Two congruent circles intersect each other inf points A and B. Solution: We have two congruent circles cb that they intersect each other at A and B. A line segment passing through A, meets the circles at P and Q.

Let us draw the common chord AB. Since angles subtended by equal chords in the congruent circles are equal. The perpendicular bisector of BC passes through O.

Join OB and OC. Suppose it cuts circumcirde at P. Solution: i interior ii exterior iii diameter iv semicircle v the chord vi three Ex Solution: Let us draw **ch 9 maths class 10 in hindi inc** pairs of circles as shown below: We have Figure Maximum number of common points i nil ii one �i two Thus, two circles can have at the most two points in common. RD Sharma Class 12 Solutions. Watch Hndi Videos.

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