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RS Aggarwal Solutions for Class 9 Maths Chapter 10 Quadrilaterals Byjus Class 8 Maths Chapter 6 Days On further calculation 2 ? DAE = o � o By subtraction 2 ? DAE = 30 o By division ? DAE = 15 o 5. Solution: It is given that BM ? AC and DN ? AC From the figure we know that ? DON and ? MOB are vertically opposite angles ? . RS Aggarwal Solutions for Class 9 Maths Chapter 10 Quadrilaterals Exercise 10(B) 1. Solution: We know that in a parallelogram opposite angles are equal So we get ? A = ? C = 72 o We that that in a parallelogram the sum of all the angles is o It can be written as ? A + ? B + ? C + ? D = o By substituting the values in the above equation. RS Aggarwal Solutions for Class 9 Maths Chapter 18 Mean, Median and Mode of Ungrouped Data Mean = sum of numbers/ total numbers By substituting the values Mean = (53 + 59 + 61 + 67 + 71 + 73 + 79)/7 On further calculation Mean = /7 So we get Mean = 66 1/7 Therefore, the mean of all prime numbers between 50 and 80 is 66 1/7. 2. Solution.

M Saraswati Vidya mandir rajgit. Answer: A perpendicular bisector is a perpendicular line passing through the midpoint of any line. July bbyjus, The syllabus mainly consists of the construction of various geometrical shapes and figures, like bisecting angles or lines. January 19, at pm Reply. He is the mentor for most of the students who cannot afford costly tuition classes.

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